State the equation for kinetic energy of rolling motion?
Question: State the equation for kinetic energy of rolling motion?
The equation for kinetic energy of rolling motion is given by the sum of the translational kinetic energy and the rotational kinetic energy of a rolling object. The translational kinetic energy is equal to 1/2 times the mass of the object times its linear velocity squared, while the rotational kinetic energy is equal to 1/2 times the moment of inertia of the object times its angular velocity squared. Therefore, the equation for kinetic energy of rolling motion is given by:
KE = 1/2mv^2 + 1/2Iω^2
where KE is the total kinetic energy, m is the mass of the object, v is its linear velocity, I is the moment of inertia of the object, and ω is its angular velocity. This equation shows that the total kinetic energy of a rolling object is dependent on both its linear and angular motion, and provides a useful tool for understanding and analyzing the energy associated with rolling objects.
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