# A body of mass 0.1kg falling freely under gravity takes 10 second to reach the ground. Calculate kinetic energy & potential energy of the body, when the body has travelled for 6 seconds.

Tuesday, March 29, 2022
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**Question: A body of mass 0.1kg falling freely under gravity takes 10 second to reach the ground. Calculate kinetic energy & potential energy of the body, when the body has travelled for 6 seconds.**

Given: m=0.1kgm,u=0,

t=6sec, a=g

∴ From v=u+at

v=0+9.8∗6

v=58.8m/s

∴ kinetic energy of the body, when the body has travelled for 6 seconds, is

K.E = (1/2)mv^2

K.E = 172.9J

To Find Potential Energy (PE):

Distance travelled by the body in 10 sec, is

S =ut+(1/2) gt^2

=490m

Distance travelled by the body in 6 sec is

S' =176.4m

∴h=S –S'

=490–176.4

=313.6m

∴P.E=mgh

=0.1∗9.8∗313.6

=307.3J.

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