# A body of mass 0.1kg falling freely under gravity takes 10 second to reach the ground. Calculate kinetic energy & potential energy of the body, when the body has travelled for 6 seconds.

Question: A body of mass 0.1kg falling freely under gravity takes 10 second to reach the ground. Calculate kinetic energy & potential energy of the body, when the body has travelled for 6 seconds.

Given: m=0.1kgm,u=0,
t=6sec, a=g
∴ From v=u+at
v=0+9.8∗6
v=58.8m/s

∴ kinetic energy of the body, when the body has travelled for 6 seconds, is
K.E =  (1/2)mv^2
K.E = 172.9J
To Find Potential Energy (PE):
Distance travelled by the body in 10 sec, is
S  =ut+(1/2) gt^2
=490m
Distance travelled by the body in 6 sec is
S' =176.4m
∴h=S –S'
​      =490–176.4
=313.6m
∴P.E=mgh
=0.1∗9.8∗313.6
=307.3J.

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