Which of the following conditions is not sufficient to prove that a quadrilateral is a parallelogram?

Question: Which of the following conditions is not sufficient to prove that a quadrilateral is a parallelogram?

a. square

b. rhombus

c.rectangle

d. trapezoid ​

The condition "square" is not sufficient to prove that a quadrilateral is a parallelogram.

A square is a special type of quadrilateral that has four equal sides and four right angles. While a square does meet some of the criteria of a parallelogram, such as having opposite sides that are parallel, it is not enough to prove that a quadrilateral is a parallelogram.

In order to prove that a quadrilateral is a parallelogram, we need to show that both pairs of opposite sides are parallel. This can be demonstrated through various methods, such as showing that the opposite sides are congruent, or that the opposite angles are congruent.

On the other hand, a rhombus, rectangle, and trapezoid all meet the criteria of a parallelogram, since they all have opposite sides that are parallel.

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