Write a c program to perform array multiplication?

Question: Write a c program to perform array multiplication?

Array multiplication is a common operation in many programming tasks, such as matrix multiplication, image processing, and linear algebra. In this blog post, we will learn how to write a C program to perform array multiplication using pointers and dynamic memory allocation.

First, let us define what array multiplication is. Given two arrays A and B of the same size n, the array multiplication C = A * B is defined as follows:

C[i] = A[i] * B[i] for i = 0, 1, ..., n-1

For example, if A = [1, 2, 3] and B = [4, 5, 6], then C = [4, 10, 18].

To write a C program to perform array multiplication, we need to do the following steps:

1. Declare three pointers to store the addresses of the arrays A, B, and C.

2. Ask the user to enter the size of the arrays and store it in a variable n.

3. Allocate memory for the arrays A, B, and C using the malloc function and check for errors.

4. Ask the user to enter the elements of the arrays A and B and store them using pointer arithmetic.

5. Perform array multiplication by looping through the arrays A and B and storing the result in C using pointer arithmetic.

6. Display the result array C using pointer arithmetic.

7. Free the memory allocated for the arrays A, B, and C using the free function.

The following is a possible implementation of the above steps in C:

#include <stdio.h>

#include <stdlib.h>

int main()

{

    // Declare three pointers to store the addresses of the arrays

    int *A, *B, *C;

    // Declare a variable to store the size of the arrays

    int n;

    // Ask the user to enter the size of the arrays

    printf("Enter the size of the arrays: ");

    scanf("%d", &n);

    // Allocate memory for the arrays A, B, and C using malloc and check for errors

    A = (int *)malloc(n * sizeof(int));

    if (A == NULL)

    {

        printf("Memory allocation failed for A.\n");

        exit(1);

    }

    B = (int *)malloc(n * sizeof(int));

    if (B == NULL)

    {

        printf("Memory allocation failed for B.\n");

        exit(1);

    }

    C = (int *)malloc(n * sizeof(int));

    if (C == NULL)

    {

        printf("Memory allocation failed for C.\n");

        exit(1);

    }

    // Ask the user to enter the elements of the arrays A and B

    printf("Enter the elements of array A: ");

    for (int i = 0; i < n; i++)

    {

        scanf("%d", A + i); // Equivalent to scanf("%d", &A[i])

    }

    printf("Enter the elements of array B: ");

    for (int i = 0; i < n; i++)

    {

        scanf("%d", B + i); // Equivalent to scanf("%d", &B[i])

    }

    // Perform array multiplication by looping through the arrays A and B

    for (int i = 0; i < n; i++)

    {

        *(C + i) = *(A + i) * *(B + i); // Equivalent to C[i] = A[i] * B[i]

    }

    // Display the result array C

    printf("The result of array multiplication is: ");

    for (int i = 0; i < n; i++)

    {

        printf("%d ", *(C + i)); // Equivalent to printf("%d ", C[i])

    }

    printf("\n");

    // Free the memory allocated for the arrays A, B, and C

    free(A);

    free(B);

    free(C);

    

    return 0;