Rank the following compounds in order of increasing strength of intermolecular forces, putting the molecule with the weakest intermolecular force first.

Question: Rank the following compounds in order of increasing strength of intermolecular forces, putting the molecule with the weakest intermolecular force first.

The strength of intermolecular forces increases in the following order:

• London dispersion forces (LDF): The weakest intermolecular force. These forces are caused by the temporary uneven distribution of electrons in a molecule.
• Dipole-dipole forces: These forces are stronger than LDFs and are caused by the presence of permanent dipoles in a molecule.
• Hydrogen bonding: The strongest intermolecular force. This force is caused by the attraction between a hydrogen atom bonded to a highly electronegative atom (such as nitrogen, oxygen, or fluorine) and a lone pair of electrons on another atom.

Based on this, the order of increasing strength of intermolecular forces for the following compounds is:

• CH4 (methane): This molecule is nonpolar and only has LDFs.
• CH3OH (methanol): This molecule is polar and has both LDFs and dipole-dipole forces.
• HF (hydrogen fluoride): This molecule is polar and has both LDFs, dipole-dipole forces, and hydrogen bonding.

Therefore, the order of increasing strength of intermolecular forces is:

1. CH4
2. CH3OH
3. HF

I hope this helps! Let me know if you have any other questions.

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